Task:
A bookseller has lots of books classified in 26 categories labeled A, B, ... Z. Each book has a code c of 3, 4, 5 or more characters. The 1st character of a code is a capital letter which defines the book category.
In the bookseller's stocklist each code c is followed by a space and by a positive integer n (int n >= 0) which indicates the quantity of books of this code in stock.
For example an extract of a stocklist could be:
L = {"ABART 20", "CDXEF 50", "BKWRK 25", "BTSQZ 89", "DRTYM 60"}.
or
L = ["ABART 20", "CDXEF 50", "BKWRK 25", "BTSQZ 89", "DRTYM 60"] or ....
You will be given a stocklist (e.g. : L) and a list of categories in capital letters e.g :
M = {"A", "B", "C", "W"}
or
M = ["A", "B", "C", "W"] or ...
and your task is to find all the books of L with codes belonging to each category of M and to sum their quantity according to each category.
For the lists L and M of example you have to return the string (in Haskell/Clojure/Racket a list of pairs):
(A : 20) - (B : 114) - (C : 50) - (W : 0)
where A, B, C, W are the categories, 20 is the sum of the unique book of category A, 114 the sum corresponding to "BKWRK" and "BTSQZ", 50 corresponding to "CDXEF" and 0 to category 'W' since there are no code beginning with W.
If L or M are empty return string is "" (Clojure and Racket should return an empty array/list instead).
Note:
In the result codes and their values are in the same order as in M.
Solution:
def stock_list(listOfArt, listOfCat):
if (len(listOfArt) == 0) or (len(listOfCat) == 0):
return ""
result = ""
for cat in listOfCat:
total = 0
for book in listOfArt:
if (book[0] == cat[0]):
total += int(book.split(" ")[1])
if (len(result) != 0):
result += " - "
result += "(" + str(cat) + " : " + str(total) + ")"
return result
b = ["ROXANNE 102", "RHODODE 123", "BKWRKAA 125", "BTSQZFG 239", "DRTYMKH 060"]
c = ["U", "V", "R"]
print(stock_list(b, c))
Help the bookseller ! Solutions | Codewars
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